初中
数学
中等
来源: 教材例题
知识点: 初中数学
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您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
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08:59:12","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"7","is_correct":1},{"id":"B","content":"8","is_correct":0},{"id":"C","content":"6","is_correct":0},{"id":"D","content":"3.5","is_correct":0}]},{"id":223,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"一个三角形的内角和是_空白处_度。","answer":"180","explanation":"根据三角形内角和定理,任意一个三角形的三个内角之和恒等于180度。这是七年级几何学习中的基本知识点,适用于所有类型的三角形,包括锐角三角形、直角三角形和钝角三角形。因此,空白处应填写180。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:40:35","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1888,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某校七年级开展‘节约用水’主题调查活动,随机抽取了50名学生记录一周内每天的用水量(单位:升),并将数据整理成频数分布表如下:\n\n| 用水量区间(升) | 频数 |\n|------------------|------|\n| 0 ≤ x < 5 | 8 |\n| 5 ≤ x < 10 | 15 |\n| 10 ≤ x < 15 | 18 |\n| 15 ≤ x < 20 | 7 |\n| 20 ≤ x < 25 | 2 |\n\n若该校七年级共有600名学生,根据样本估计总体,大约有多少名学生的周用水量不低于10升但低于20升?","answer":"B","explanation":"首先,从频数分布表中找出用水量在10 ≤ x < 20区间内的频数,即10 ≤ x < 15和15 ≤ x < 20两个区间的频数之和:18 + 7 = 25人。这25人占样本总数50人的比例为25 ÷ 50 = 0.5。然后用这个比例估计总体:600 × 0.5 = 300人。因此,大约有300名学生的周用水量不低于10升但低于20升。本题考查数据的收集、整理与描述中的频数分布与总体估计,要求学生理解样本与总体的关系,并能进行合理的比例推算。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-07 10:13:06","updated_at":"2026-01-07 10:13:06","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"240","is_correct":0},{"id":"B","content":"300","is_correct":1},{"id":"C","content":"360","is_correct":0},{"id":"D","content":"420","is_correct":0}]},{"id":2147,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在解方程时,将方程 2x + 3 = 7 的两边同时减去3,得到 2x = 4,然后两边同时除以2,得到 x = 2。这一过程主要运用了等式的哪一条基本性质?","answer":"D","explanation":"该学生在解题过程中,先两边同时减去3(运用了等式性质1:两边同时减去同一个数,等式仍成立),再两边同时除以2(运用了等式性质2:两边同时除以同一个不为零的数,等式仍成立)。因此,整个过程中综合运用了等式的基本性质,选项D最全面准确。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 13:00:46","updated_at":"2026-01-09 13:00:46","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"等式两边同时加上同一个数,等式仍然成立","is_correct":0},{"id":"B","content":"等式两边同时减去同一个数,等式仍然成立","is_correct":0},{"id":"C","content":"等式两边同时乘或除以同一个不为零的数,等式仍然成立","is_correct":0},{"id":"D","content":"以上三条性质都运用了","is_correct":1}]},{"id":1708,"subject":"语文","grade":"五年级","stage":"小学","type":"填空题","content":"春天的早晨,阳光洒在草地上,露珠在叶片上闪闪发亮,像一颗颗晶莹的_。","answer":"珍珠","explanation":"本题考查五年级学生运用比喻修辞手法的能力以及对自然景物的观察与表达能力。句子中‘露珠在叶片上闪闪发亮’,需要用一个恰当的词语来形容其晶莹剔透、圆润发亮的特点。‘珍珠’是常见且符合语境的喻体,能生动形象地表现露珠的美丽,符合五年级语文课程中‘学习使用比喻句’的知识点。该题贴近生活,语言优美,难度适中,适合学生理解与作答。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 14:01:47","updated_at":"2026-01-06 14:01:47","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":551,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"某学生记录了一周内每天完成的数学练习题数量,分别为:8道、10道、7道、9道、11道、6道、12道。这组数据的众数是多少?","answer":"D","explanation":"众数是一组数据中出现次数最多的数。观察数据:6、7、8、9、10、11、12,每个数都只出现了一次,没有任何一个数重复出现。因此,这组数据中没有众数。正确答案是D。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:09:31","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"6","is_correct":0},{"id":"B","content":"8","is_correct":0},{"id":"C","content":"10","is_correct":0},{"id":"D","content":"没有众数","is_correct":1}]},{"id":190,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"下列运算中,正确的是( )。","answer":"D","explanation":"本题考查的是七年级整式加减中的同类项合并。同类项是指所含字母相同,并且相同字母的指数也相同的项,只有同类项才能合并。选项A中,3a和2b不是同类项,不能合并,错误;选项B中,5y² - 2y² = 3y²,而不是3,漏掉了字母部分,错误;选项C中,4x²y和5xy²所含字母的指数不同(x和y的次数不对应),不是同类项,不能合并,错误;选项D中,7mn和3nm是同类项(因为mn = nm),可以合并,7mn - 3nm = 7mn - 3mn = 4mn,正确。因此,正确答案是D。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:02:14","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3a + 2b = 5ab","is_correct":0},{"id":"B","content":"5y² - 2y² = 3","is_correct":0},{"id":"C","content":"4x²y - 5xy² = -x²y","is_correct":0},{"id":"D","content":"7mn - 3nm = 4mn","is_correct":1}]},{"id":264,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"一个多边形的内角和是外角和的3倍,则这个多边形的边数是___。","answer":"8","explanation":"多边形的外角和恒为360度。设这个多边形的边数为n,则其内角和为(n - 2) × 180度。根据题意,内角和是外角和的3倍,即(n - 2) × 180 = 3 × 360。计算得(n - 2) × 180 = 1080,两边同时除以180得n - 2 = 6,解得n = 8。因此,这个多边形是八边形。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"中等","points":1,"is_active":1,"created_at":"2025-12-29 14:55:38","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":243,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在计算一个数的相反数时,误将该数加上了5,结果得到了8。那么这个数的正确相反数应该是____。","answer":"-3","explanation":"设这个数为x。根据题意,某学生误将x加上5得到8,即x + 5 = 8,解得x = 3。这个数的相反数是-3。因此,正确答案是-3。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:42:03","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2255,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在数轴上从点A出发,先向右移动5个单位长度到达点B,再向左移动8个单位长度到达点C。如果点A表示的数是-2,那么点C表示的数是多少?","answer":"D","explanation":"点A表示的数是-2。向右移动5个单位长度,即-2 + 5 = 3,到达点B。再从点B向左移动8个单位长度,即3 - 8 = -5,因此点C表示的数是-5。选项D正确。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 16:03:06","updated_at":"2026-01-09 16:03:06","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"-5","is_correct":0},{"id":"B","content":"-10","is_correct":0},{"id":"C","content":"1","is_correct":0},{"id":"D","content":"-5","is_correct":1}]}]