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数学
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x)。根据得分规则,总得分为3x - 1×(120 - x) = 280。化简方程得:3x - 120 + x = 280,即4x = 400,解得x = 100。因此,他们答对了100道题。本题考查一元一次方程的实际应用,属于简单难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 03:12:36","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1927,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某班级组织一次环保活动,收集可回收垃圾。第一周收集了x千克废纸,第二周收集的比第一周的2倍少3千克。已知两周共收集了17千克废纸,则第一周收集了多少千克?","answer":"C","explanation":"设第一周收集废纸x千克,则第二周收集了(2x - 3)千克。根据题意,两周共收集17千克,可列方程:x + (2x - 3) = 17。化简得3x - 3 = 17,移项得3x = 20,解得x = 7。因此第一周收集了7千克废纸。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-07 13:18:07","updated_at":"2026-01-07 13:18:07","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"5","is_correct":0},{"id":"B","content":"6","is_correct":0},{"id":"C","content":"7","is_correct":1},{"id":"D","content":"8","is_correct":0}]},{"id":932,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级环保活动中,某学生记录了5个小组每周回收的废纸重量(单位:千克),分别为:3.5、4.2、3.8、4.0、4.5。为了计算平均每个小组回收的废纸重量,需要先求出总重量,再除以小组数量。那么这5个小组平均每周回收废纸____千克。","answer":"4.0","explanation":"首先将5个小组回收的废纸重量相加:3.5 + 4.2 + 3.8 + 4.0 + 4.5 = 20.0(千克)。然后将总重量除以小组数量5:20.0 ÷ 5 = 4.0(千克)。因此,平均每个小组每周回收废纸4.0千克。本题考查数据的收集与整理中的平均数计算,属于简单难度的基础运算。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 03:03:40","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":663,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生调查了班级同学每天使用手机的时间(单位:分钟),将数据整理后发现,使用时间在30分钟以下的有8人,30到60分钟的有12人,60到90分钟的有15人,90分钟以上的有5人。则使用手机时间在60分钟及以上的学生占总人数的百分比是____%。","answer":"50","explanation":"首先计算总人数:8 + 12 + 15 + 5 = 40人。使用手机时间在60分钟及以上的包括“60到90分钟”和“90分钟以上”两组,共15 + 5 = 20人。因此所占百分比为(20 ÷ 40) × 100% = 50%。本题考查数据的收集、整理与描述中的频数统计与百分比计算,属于简单难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:16:54","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2502,"subject":"数学","grade":"九年级","stage":"初中","type":"选择题","content":"如图,一个圆形花坛被两条互相垂直的直径分成四个相等的扇形区域。现要在其中一个扇形区域内修建一个矩形观景台,要求矩形的两个顶点在圆弧上,另外两个顶点分别在两条半径上,且矩形的一边与其中一条半径重合。若花坛的半径为4米,则该矩形观景台的最大可能面积为多少平方米?","answer":"A","explanation":"设矩形在半径上的边长为x(0 < x < 4),由于矩形的一个角位于圆心,且两边分别沿两条垂直半径方向,则其对角顶点位于圆弧上,满足圆的方程x² + y² = 4² = 16。因为矩形两边分别平行于两条半径,所以另一边的长度为y = √(16 - x²)。但注意:此处矩形实际是以圆心为一个顶点,两边沿半径方向延伸长度x和y,但由于题目要求矩形两个顶点在圆弧上,另两个在半径上,且一边与半径重合,因此更合理的建模是:设矩形与半径重合的一边长度为x,则其对边也在圆弧上,由对称性和几何关系可得另一边长为x(因角度为90°,形成等腰直角结构)。进一步分析可知,当矩形为正方形时面积最大。利用坐标法:设矩形顶点为(0,0)、(x,0)、(x,x)、(0,x),则点(x,x)必须在圆内或圆上,即x² + x² ≤ 16 → 2x² ≤ 16 → x² ≤ 8 → x ≤ 2√2。此时面积S = x² ≤ 8。当x = 2√2时,点(2√2, 2√2)恰好在圆上(因(2√2)² + (2√2)² = 8 + 8 = 16),满足条件。故最大面积为8平方米。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-10 15:25:56","updated_at":"2026-01-10 15:25:56","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"8","is_correct":1},{"id":"B","content":"4√2","is_correct":0},{"id":"C","content":"6","is_correct":0},{"id":"D","content":"4","is_correct":0}]},{"id":2192,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在记录一周内每天气温变化时,发现某天的气温比前一天上升了5℃,记作+5℃。如果第二天的气温又比当天下降了8℃,那么第二天的气温变化应记作多少?","answer":"B","explanation":"气温下降应使用负数表示。题目中明确指出‘下降了8℃’,因此变化量应记为-8℃。选项B正确。其他选项中,A表示上升,C和D是数值计算错误或符号错误,不符合题意。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 14:25:31","updated_at":"2026-01-09 14:25:31","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"+8℃","is_correct":0},{"id":"B","content":"-8℃","is_correct":1},{"id":"C","content":"+3℃","is_correct":0},{"id":"D","content":"-3℃","is_correct":0}]},{"id":1913,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某班级进行了一次数学测验,老师将成绩分为A、B、C、D四个等级,并制作了频数分布表。已知A等级有12人,B等级有18人,C等级有15人,D等级有5人。请问该班级参加测验的学生总人数是多少?","answer":"C","explanation":"本题考查数据的收集、整理与描述中的频数统计。总人数等于各等级人数之和:12(A等级) + 18(B等级) + 15(C等级) + 5(D等级) = 50(人)。因此,正确答案是C选项。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-07 13:12:19","updated_at":"2026-01-07 13:12:19","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"40人","is_correct":0},{"id":"B","content":"45人","is_correct":0},{"id":"C","content":"50人","is_correct":1},{"id":"D","content":"55人","is_correct":0}]},{"id":683,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级图书角的统计中,某学生记录了上周同学们借阅科普类书籍和文学类书籍的数量。已知科普类书籍借出15本,文学类书籍借出23本,这两类书籍的平均借阅量为___本。","answer":"19","explanation":"本题考查数据的收集、整理与描述中的平均数计算。平均数 = 总数量 ÷ 总份数。将科普类和文学类书籍的借阅数量相加:15 + 23 = 38(本),再除以类别数2,得到平均借阅量为38 ÷ 2 = 19(本)。因此,空白处应填19。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:31:03","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]