初中
数学
中等
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知识点: 初中数学
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[{"id":434,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"12人","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:37:48","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":852,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级图书整理活动中,某学生统计了同学们捐赠的书籍数量。已知捐赠的数学书比语文书多8本,且两种书共捐赠了36本。设语文书捐赠了x本,则根据题意可列方程为:x + (x + 8) = 36。解这个方程,语文书捐赠了___本。","answer":"14","explanation":"根据题意,语文书为x本,数学书比语文书多8本,即为(x + 8)本。两者总数为36本,因此列出方程:x + (x + 8) = 36。化简得:2x + 8 = 36,移项得:2x = 28,解得:x = 14。所以语文书捐赠了14本。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 01:05:48","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1949,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在平面直角坐标系中绘制了一个四边形ABCD,其顶点坐标分别为A(1, 2)、B(5, 2)、C(7, -1)、D(3, -1)。若将该四边形沿x轴正方向平移3个单位,再沿y轴负方向平移4个单位,则平移后点C的坐标为____。","answer":"(10, -5)","explanation":"平移规则:横坐标加3,纵坐标减4。原C(7, -1) → 7+3=10,-1-4=-5。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:14:25","updated_at":"2026-01-07 14:14:25","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":424,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次班级数学测验中,老师收集了10名学生的成绩(单位:分)如下:85,78,92,88,76,90,84,89,81,87。如果老师想用一个统计量来代表这次测验的整体水平,并且希望这个值能反映大多数学生的成绩情况,那么最合适的统计量是:","answer":"B","explanation":"题目要求选择一个能代表整体水平并反映大多数学生成绩情况的统计量。首先观察数据:85,78,92,88,76,90,84,89,81,87。这些数据分布较为均匀,没有明显的极端值(如特别高或特别低的分数),但也没有重复出现的数值,因此众数不存在或无法体现‘大多数’。最大值(92)仅代表最高分,不能反映整体。平均数虽然能反映整体平均水平,但容易受极端值影响;而中位数是将数据按大小顺序排列后位于中间的值,能较好地代表中间水平,避免极端值干扰。将数据从小到大排列:76,78,81,84,85,87,88,89,90,92。共有10个数据,中位数为第5和第6个数的平均数,即(85 + 87) ÷ 2 = 86。这个值位于数据中间位置,能较好地反映大多数学生的成绩集中趋势,因此最合适。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:32:56","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"平均数","is_correct":0},{"id":"B","content":"中位数","is_correct":1},{"id":"C","content":"众数","is_correct":0},{"id":"D","content":"最大值","is_correct":0}]},{"id":1034,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级环保活动中,某学生记录了连续5天每天收集的废旧纸张重量(单位:千克),分别为2.5、3.0、2.8、3.2和2.7。如果这些数据被用来制作频数分布表,并将数据按0.5千克为组距进行分组,那么重量在2.5千克到3.0千克(含2.5千克,不含3.0千克)这一组中的数据个数是____。","answer":"3","explanation":"首先确定分组区间:以0.5千克为组距,从2.5开始分组,则分组为[2.5, 3.0)、[3.0, 3.5)等。题目要求统计落在[2.5, 3.0)区间内的数据个数。原始数据为2.5、3.0、2.8、3.2、2.7。其中,2.5、2.8、2.7均大于等于2.5且小于3.0,共3个数据;而3.0属于下一组[3.0, 3.5),不计入本组。因此,该组中有3个数据。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 06:01:33","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":159,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"下列各数中,属于正整数的是( )","answer":"D","explanation":"正整数是指大于0的整数。选项A是负整数,选项B是0(既不是正数也不是负数),选项C是小数,只有选项D的7是大于0的整数,因此选D。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-24 11:57:36","updated_at":"2025-12-24 11:57:36","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"-3","is_correct":0},{"id":"B","content":"0","is_correct":0},{"id":"C","content":"1.5","is_correct":0},{"id":"D","content":"7","is_correct":1}]},{"id":2262,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"在数轴上,点A表示的数是-3,点B与点A之间的距离为5个单位长度,且点B在原点的右侧。那么点B表示的数是___。","answer":"B","explanation":"点A表示的数是-3,点B与点A的距离为5个单位长度。由于在数轴上向右移动数值增大,且点B在原点右侧,说明点B表示的数大于0。从-3向右移动5个单位:-3 + 5 = 2,因此点B表示的数是2。选项B正确。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 16:03:06","updated_at":"2026-01-09 16:03:06","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"-8","is_correct":0},{"id":"B","content":"2","is_correct":1},{"id":"C","content":"8","is_correct":0},{"id":"D","content":"-2","is_correct":0}]},{"id":998,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生调查了班级同学最喜欢的运动项目,收集数据后制作了频数分布表。其中喜欢跳绳的有8人,喜欢踢毽子的有5人,喜欢跑步的有12人,喜欢打篮球的有15人。则喜欢打篮球的人数占总人数的百分比是______%。","answer":"37.5","explanation":"首先计算总人数:8 + 5 + 12 + 15 = 40(人)。喜欢打篮球的人数为15人,因此所占百分比为 (15 ÷ 40) × 100% = 37.5%。本题考查数据的收集、整理与描述中的百分比计算,属于简单应用。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 04:50:48","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2362,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"如图,在平面直角坐标系中,点A(0, 4),点B(6, 0),点C是线段AB上的一点,且满足AC : CB = 1 : 2。点D是点C关于直线y = x的对称点。若一次函数y = kx + b的图像经过点D和原点O(0, 0),则k的值为多少?","answer":"B","explanation":"首先根据定比分点公式求出点C的坐标。由于AC:CB = 1:2,即C将AB分为1:2,因此C的坐标为:x = (2×0 + 1×6)\/(1+2) = 6\/3 = 2,y = (2×4 + 1×0)\/3 = 8\/3,故C(2, 8\/3)。点D是C关于直线y = x的对称点,根据轴对称性质,对称点坐标互换,即D(8\/3, 2)。一次函数y = kx + b经过原点O(0,0)和点D(8\/3, 2),代入原点得b = 0,故函数为y = kx。将D点坐标代入得:2 = k × (8\/3),解得k = 2 × 3 \/ 8 = 6\/8 = 3\/4。因此正确答案为B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 11:13:35","updated_at":"2026-01-10 11:13:35","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"2\/3","is_correct":0},{"id":"B","content":"3\/4","is_correct":1},{"id":"C","content":"4\/5","is_correct":0},{"id":"D","content":"5\/6","is_correct":0}]},{"id":846,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次环保活动中,某班级学生收集废旧纸张和塑料瓶两类物品。已知收集废旧纸张的人数比收集塑料瓶的人数多5人,两类活动共有31人参加,且每人只参加一类。若设收集塑料瓶的人数为x,则根据题意可列出一元一次方程:_x + (x + 5) = 31_,解得x = _13_,因此收集废旧纸张的人数是_18_人。","answer":"x + (x + 5) = 31;13;18","explanation":"设收集塑料瓶的人数为x,则收集废旧纸张的人数为x + 5。根据总人数为31人,可列方程:x + (x + 5) = 31。化简得2x + 5 = 31,解得2x = 26,x = 13。因此收集塑料瓶的有13人,收集废旧纸张的有13 + 5 = 18人。本题考查一元一次方程的实际应用,结合生活情境,帮助学生理解方程建模的基本方法。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 01:02:32","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]