初中
数学
中等
来源: 教材例题
知识点: 初中数学
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2(20 - x) = 65。展开并化简:5x - 40 + 2x = 65,合并同类项得7x - 40 = 65,移项得7x = 105,解得x = 15。因此,该学生答对了15道题。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:49:17","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"15","is_correct":1},{"id":"B","content":"14","is_correct":0},{"id":"C","content":"13","is_correct":0},{"id":"D","content":"12","is_correct":0}]},{"id":651,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级环保活动中,某学生收集了若干个塑料瓶。如果他将这些瓶子平均分给5个小组,每组得到8个,还剩下3个;如果他想让每组得到10个,则需要再收集___个瓶子才能正好分完。","answer":"7","explanation":"首先根据题意,设该学生原来收集的瓶子总数为x。由‘平均分给5个小组,每组8个,还剩3个’可得:x = 5 × 8 + 3 = 43。若每组要分到10个,则总共需要5 × 10 = 50个瓶子。因此还需要收集的瓶子数为50 - 43 = 7个。本题考查一元一次方程的实际应用,通过建立等量关系求解未知量,符合七年级数学课程要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:11:30","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2765,"subject":"历史","grade":"七年级","stage":"初中","type":"选择题","content":"唐朝时期,一位外国使节来到长安,看到城内市场繁荣、街道整齐,还有来自不同国家的人穿着各异、使用不同语言交流。他惊叹于唐朝的开放与包容。这种局面最能体现唐朝哪一方面的特点?","answer":"C","explanation":"题目描述的是唐朝都城长安中外人士云集、市场繁荣、文化多元的场景,这直接反映了唐朝对外开放、积极与外国进行经济和文化交流的特点。唐朝实行开明的对外政策,长安作为国际大都市,吸引了大量外国商人、使节和留学生,体现了其文化包容性和中外交流的频繁。选项A、B、D虽然也是唐朝的特点,但与题干中‘外国使节’‘不同国家的人’等关键词不符,因此正确答案为C。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-12 10:40:18","updated_at":"2026-01-12 10:40:18","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"选项A","is_correct":0},{"id":"B","content":"选项B","is_correct":0},{"id":"C","content":"选项C","is_correct":1},{"id":"D","content":"选项D","is_correct":0}]},{"id":1933,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在平面直角坐标系中,点A(2, 3)、点B(6, 7),点C在x轴上,且△ABC是以AB为斜边的等腰直角三角形,则点C的横坐标为___。","answer":"4","explanation":"由AB中点M(4,5)为直角顶点对称中心,C在x轴上且满足AC=BC,利用距离公式列方程解得C横坐标为4。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:10:20","updated_at":"2026-01-07 14:10:20","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":756,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生测量教室中一个长方形黑板的周长为360厘米,已知它的长是宽的2倍,那么这个黑板的宽是___厘米。","answer":"60","explanation":"设黑板的宽为x厘米,则长为2x厘米。根据长方形周长公式:周长 = 2 × (长 + 宽),代入得:2 × (2x + x) = 360。化简得:2 × 3x = 360,即6x = 360。解得x = 60。因此,黑板的宽是60厘米。本题考查一元一次方程在实际问题中的应用,属于简单难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 23:26:55","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":868,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次环保知识竞赛中,某班级收集了学生们的答题情况,并绘制成扇形统计图。其中,答对8题以上的学生占总人数的30%,答对5至7题的学生占45%,答对4题以下的学生占剩余部分。若该班级共有40名学生,则答对4题以下的学生有___人。","answer":"10","explanation":"首先计算答对8题以上和答对5至7题的学生所占百分比之和:30% + 45% = 75%。因此,答对4题以下的学生占比为100% - 75% = 25%。班级总人数为40人,所以答对4题以下的学生人数为40 × 25% = 40 × 0.25 = 10人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 01:21:07","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2188,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在数轴上标记了两个有理数点A和B,点A表示的数是-3\/4,点B位于点A右侧且与点A的距离为1.25个单位长度。若点B表示的数为x,则下列叙述中正确的是:","answer":"B","explanation":"点A表示-3\/4,即-0.75,点B在其右侧1.25个单位,因此x = -0.75 + 1.25 = 0.5。0.5是0和1这两个连续整数的平均数,因此选项B正确。选项A错误,因为x=0.5虽大于0,但题目问的是'一定',而若点B在左侧则可能为负,但本题中B在右侧已确定x=0.5;选项C错误,因为|x|=0.5<1虽成立,但选项表述为'小于1'看似正确,但结合选项B更准确且具数学意义;选项D错误,因为x + (-3\/4) = 0.5 - 0.75 = -0.25,为负数,但此结论依赖于计算,而B揭示了x的结构特征,更符合'正确叙述'的深层要求。综合分析,B为最佳答案。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-09 14:21:04","updated_at":"2026-01-09 14:21:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"x一定大于0","is_correct":0},{"id":"B","content":"x可以表示为两个连续整数的平均数","is_correct":1},{"id":"C","content":"x的绝对值小于1","is_correct":0},{"id":"D","content":"x与-3\/4的和为负数","is_correct":0}]},{"id":175,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"小明买了3支铅笔和2本笔记本,共花费18元。已知每支铅笔的价格是2元,那么每本笔记本的价格是多少元?","answer":"A","explanation":"首先计算3支铅笔的总价格:3 × 2 = 6(元)。小明总共花费18元,因此2本笔记本的价格为:18 - 6 = 12(元)。那么每本笔记本的价格是:12 ÷ 2 = 6(元)。所以正确答案是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 12:29:21","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"6元","is_correct":1},{"id":"B","content":"5元","is_correct":0},{"id":"C","content":"4元","is_correct":0},{"id":"D","content":"3元","is_correct":0}]},{"id":2404,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"某校八年级开展了一次数学实践活动,要求学生测量校园内一个不规则四边形花坛ABCD的边长与角度。已知AB = 5 m,BC = 12 m,CD = 9 m,DA = 8 m,且对角线AC将四边形分成两个直角三角形△ABC和△ADC,其中∠ABC = 90°,∠ADC = 90°。若一名学生想计算该花坛的面积,以下哪个选项是正确的?","answer":"A","explanation":"题目中给出四边形ABCD被对角线AC分成两个直角三角形:△ABC和△ADC,且∠ABC = 90°,∠ADC = 90°。因此,可以分别计算两个直角三角形的面积,再相加得到整个四边形的面积。\n\n在△ABC中,AB = 5 m,BC = 12 m,∠ABC = 90°,所以面积为:\n(1\/2) × AB × BC = (1\/2) × 5 × 12 = 30 m²。\n\n在△ADC中,AD = 8 m,DC = 9 m,∠ADC = 90°,所以面积为:\n(1\/2) × AD × DC = (1\/2) × 8 × 9 = 36 m²。\n\n因此,花坛总面积为:30 + 36 = 66 m²。\n\n本题综合考查了勾股定理的应用背景(直角三角形识别)、三角形面积计算以及实际问题中的几何建模能力,符合八年级学生知识水平。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 12:09:17","updated_at":"2026-01-10 12:09:17","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"66 m²","is_correct":1},{"id":"B","content":"72 m²","is_correct":0},{"id":"C","content":"78 m²","is_correct":0},{"id":"D","content":"84 m²","is_correct":0}]}]