初中
数学
中等
来源: 教材例题
知识点: 初中数学
答案预览
点击下方'查看答案'按钮查看详细解析并跳转到题目详情页
直接前往详情页
练习完成!
恭喜您完成了本次练习,继续加油提升自己的知识水平!
学习建议
您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":515,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"40","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:18:49","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":911,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次环保活动中,某学生收集了不同种类的垃圾,其中可回收垃圾占总量的3\/8,厨余垃圾占总量的1\/4,有害垃圾占0.125,其余为其他垃圾。如果其他垃圾的重量是2.5千克,那么这次收集垃圾的总重量是___千克。","answer":"10","explanation":"首先将各部分垃圾所占比例统一为分数形式:可回收垃圾占3\/8,厨余垃圾占1\/4 = 2\/8,有害垃圾占0.125 = 1\/8。将这些比例相加:3\/8 + 2\/8 + 1\/8 = 6\/8 = 3\/4。因此,其他垃圾占总量的1 - 3\/4 = 1\/4。已知其他垃圾为2.5千克,设总重量为x千克,则有(1\/4)x = 2.5,解得x = 2.5 × 4 = 10。所以总重量是10千克。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 02:32:30","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1324,"subject":"数学","grade":"七年级","stage":"初中","type":"解答题","content":"某城市为改善交通状况,计划在一条主干道旁修建一个矩形绿化带。绿化带的一边紧贴道路(不需要围栏),其余三边用总长为60米的环保材料围栏围成。为了提升生态效益,绿化带被划分为两个区域:一个正方形种植区用于种植灌木,另一个矩形区域用于种植草本植物。正方形种植区的一边与道路平行,且其边长比草本植物区域的宽度多2米。已知草本植物区域的长度与正方形种植区的边长相等。设草本植物区域的宽度为x米。\n\n(1)用含x的整式表示绿化带的总长度和总宽度;\n(2)根据围栏总长为60米,列出关于x的一元一次方程,并求出x的值;\n(3)若每平方米灌木种植成本为80元,草本植物为50元,求整个绿化带的总种植成本;\n(4)若城市规划要求绿化带面积不得小于200平方米,请验证该设计方案是否满足要求,并说明理由。","answer":"(1)设草本植物区域的宽度为x米,则正方形种植区的边长为(x + 2)米。\n由于草本植物区域的长度与正方形边长相等,也为(x + 2)米。\n\n绿化带的总长度(与道路平行的方向)为:正方形边长 + 草本植物区域长度 = (x + 2) + (x + 2) = 2x + 4(米)。\n\n绿化带的总宽度(垂直于道路的方向)为:草本植物区域的宽度 = x 米。\n\n答:绿化带总长度为(2x + 4)米,总宽度为x米。\n\n(2)围栏用于三边:两条宽(左右两侧)和一条长(远离道路的一侧)。\n围栏总长 = 2 × 宽度 + 长度 = 2x + (2x + 4) = 4x + 4(米)。\n\n根据题意,围栏总长为60米:\n4x + 4 = 60\n4x = 56\nx = 14\n\n答:x的值为14。\n\n(3)当x = 14时:\n正方形种植区边长 = 14 + 2 = 16(米),面积 = 16 × 16 = 256(平方米)。\n草本植物区域面积 = 长度 × 宽度 = 16 × 14 = 224(平方米)。\n\n总种植成本 = 256 × 80 + 224 × 50 = 20480 + 11200 = 31680(元)。\n\n答:总种植成本为31680元。\n\n(4)绿化带总面积 = 正方形面积 + 草本植物面积 = 256 + 224 = 480(平方米)。\n\n因为480 > 200,所以该设计方案满足绿化带面积不得小于200平方米的要求。\n\n答:满足要求,因为总面积为480平方米,大于200平方米。","explanation":"本题综合考查了整式的加减、一元一次方程、几何图形初步及实际问题的建模能力。第(1)问要求学生根据文字描述建立代数表达式,理解图形结构;第(2)问通过围栏总长建立方程,体现方程建模思想;第(3)问结合有理数运算与面积计算,考查多步运算能力;第(4)问引入不等式思想(虽未直接使用不等式符号,但需比较大小),检验方案合理性。题目情境贴近生活,结构层层递进,难度较高,适合学有余力的七年级学生挑战。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 10:55:37","updated_at":"2026-01-06 10:55:37","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":706,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生在整理班级同学最喜爱的课外活动数据时,绘制了如下扇形统计图:阅读占30%,运动占40%,音乐占20%,其他占10%。如果全班共有50名学生,那么喜欢运动的学生人数比喜欢阅读的学生多___人。","answer":"5","explanation":"首先根据百分比计算喜欢运动的学生人数:50 × 40% = 50 × 0.4 = 20(人);再计算喜欢阅读的学生人数:50 × 30% = 50 × 0.3 = 15(人)。然后用喜欢运动的人数减去喜欢阅读的人数:20 - 15 = 5(人)。因此,喜欢运动的学生比喜欢阅读的学生多5人。本题考查的是数据的收集、整理与描述中的百分比应用,属于简单难度,符合七年级数学课程内容。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:44:36","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":908,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某班级组织学生参加植树活动,原计划每天植树50棵,实际每天比原计划多种树10棵,结果提前2天完成了植树任务。那么原计划需要___天完成植树任务。","answer":"12","explanation":"设原计划需要 x 天完成任务,则总植树量为 50x 棵。实际每天植树 50 + 10 = 60 棵,用了 (x - 2) 天完成,因此有方程:60(x - 2) = 50x。解这个一元一次方程:60x - 120 = 50x → 10x = 120 → x = 12。所以原计划需要12天完成任务。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 02:28:11","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":233,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生计算一个多边形的内角和时,使用了公式 (n - 2) × 180°,其中 n 表示边数。如果这个多边形是五边形,那么它的内角和是_空白处_度。","answer":"540","explanation":"根据多边形内角和公式 (n - 2) × 180°,五边形的边数 n = 5。代入公式得:(5 - 2) × 180° = 3 × 180° = 540°。因此,五边形的内角和是540度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:41:09","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":567,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"平均数是5.2,中位数是5,众数是5","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:35:05","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":791,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次环保主题活动中,某学生统计了班级同学一周内节约用水的总量。已知前三天共节约了15升,后四天平均每天节约4升,那么这一周总共节约用水____升。","answer":"31","explanation":"根据题意,后四天平均每天节约4升,则后四天共节约 4 × 4 = 16 升。前三天共节约15升,因此一周总共节约用水为 15 + 16 = 31 升。本题考查了有理数的加减运算及实际问题中的数据处理能力,属于‘数据的收集、整理与描述’知识点,难度简单。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 00:08:44","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":284,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"8","answer":"答案待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:31:38","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":331,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的身高数据时,制作了如下频数分布表:\n身高区间(cm) | 频数\n150~155 | 4\n155~160 | 7\n160~165 | 10\n165~170 | 6\n170~175 | 3\n请问这组数据的中位数最可能落在哪个身高区间?","answer":"C","explanation":"首先计算总人数:4 + 7 + 10 + 6 + 3 = 30人。中位数是第15和第16个数据的平均值。累计频数:150~155有4人,155~160累计11人,160~165累计21人。第15和第16个数据都落在160~165区间内,因此中位数最可能位于该区间。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:39:24","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"150~155","is_correct":0},{"id":"B","content":"155~160","is_correct":0},{"id":"C","content":"160~165","is_correct":1},{"id":"D","content":"165~170","is_correct":0}]}]