初中
数学
中等
来源: 教材例题
知识点: 初中数学
答案预览
点击下方'查看答案'按钮查看详细解析并跳转到题目详情页
直接前往详情页
练习完成!
恭喜您完成了本次练习,继续加油提升自己的知识水平!
学习建议
您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":2218,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生记录了一周内每天的温度变化,规定比0℃高为正,比0℃低为负。其中某天的温度记为-3℃,另一天的温度比这一天高5℃,则这一天的温度记为___℃。","answer":"2","explanation":"题目中已知某天温度为-3℃,另一天比它高5℃,即计算-3 + 5。根据正负数加减法则,-3 + 5 = 2,因此这一天的温度记为2℃。该题考查正负数在实际情境中的加减运算,符合七年级学生对正负数意义的理解和应用要求。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 14:27:19","updated_at":"2026-01-09 14:27:19","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1937,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在平面直角坐标系中绘制了一个三角形,其三个顶点分别为 A(2, 3)、B(5, -1)、C(-1, -1)。若将该三角形沿 x 轴方向平移 _ 个单位长度后,点 A 的对应点 A' 恰好落在 y 轴上,则平移的单位长度为 ___。","answer":"2","explanation":"点 A 的横坐标为 2,要使其平移到 y 轴上(横坐标为 0),需向左平移 2 个单位。平移不改变纵坐标,仅改变横坐标。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:11:02","updated_at":"2026-01-07 14:11:02","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":279,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在平面直角坐标系中画了一个三角形,三个顶点的坐标分别为 A(1, 2)、B(4, 2) 和 C(3, 5)。若将该三角形向右平移 3 个单位,再向下平移 2 个单位,则点 C 的新坐标是?","answer":"A","explanation":"平移变换规则:向右平移 a 个单位,横坐标加 a;向下平移 b 个单位,纵坐标减 b。点 C 的原坐标是 (3, 5)。向右平移 3 个单位,横坐标变为 3 + 3 = 6;再向下平移 2 个单位,纵坐标变为 5 - 2 = 3。因此,点 C 的新坐标是 (6, 3)。选项 A 正确。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:31:07","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"(6, 3)","is_correct":1},{"id":"B","content":"(5, 7)","is_correct":0},{"id":"C","content":"(0, 3)","is_correct":0},{"id":"D","content":"(6, 7)","is_correct":0}]},{"id":2244,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在数轴上从原点出发,先向右移动5个单位长度,再向左移动8个单位长度,接着又向右移动3个单位长度,最后向左移动2个单位长度。此时该学生所在位置的数与它的相反数的和是___。","answer":"0","explanation":"首先计算该学生在数轴上的最终位置:从原点0出发,+5(向右)得5,-8(向左)得-3,+3(向右)得0,-2(向左)得-2。所以最终位置是-2。-2的相反数是2,它们的和为-2 + 2 = 0。本题综合考查了正负数在数轴上的移动表示、有理数的加减运算以及相反数的概念,要求学生在多步操作中准确计算并理解相反数的性质,属于较高难度的应用题。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-09 14:39:22","updated_at":"2026-01-09 14:39:22","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1950,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生测量一个不规则四边形花坛的四条边长,分别为3.5米、4.2米、5.1米和6.0米。若该花坛被一条对角线分成两个三角形,其中一个三角形的周长为12.8米,则另一个三角形的周长为______米。","answer":"6.0","explanation":"四边形总周长为3.5+4.2+5.1+6.0=18.8米。一个三角形周长为12.8米,包含两条边和对角线。另一三角形周长=总边长和−已知三角形中两条边+对角线=18.8−12.8=6.0米。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:14:40","updated_at":"2026-01-07 14:14:40","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1073,"subject":"数学","grade":"七年级","stage":"小学","type":"填空题","content":"某学生在调查班级同学最喜欢的课外活动时,收集了以下数据:阅读、运动、绘画、音乐。他将数据整理成频数分布表后发现,喜欢运动的人数是喜欢绘画人数的2倍,喜欢音乐的人数比喜欢绘画的多3人,喜欢阅读的人数比喜欢音乐的少1人。若总人数为30人,则喜欢绘画的人数是___。","answer":"5","explanation":"设喜欢绘画的人数为x,则喜欢运动的人数为2x,喜欢音乐的人数为x + 3,喜欢阅读的人数为(x + 3) - 1 = x + 2。根据总人数为30,可列方程:x + 2x + (x + 3) + (x + 2) = 30。合并同类项得:5x + 5 = 30,解得5x = 25,x = 5。因此,喜欢绘画的人数是5人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 08:53:20","updated_at":"2026-01-06 08:53:20","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1864,"subject":"数学","grade":"七年级","stage":"初中","type":"解答题","content":"某校七年级组织学生参加数学实践活动,需将一批实验器材分装到若干个箱子中。若每箱装8件,则剩余12件无法装下;若每箱装10件,则最后一个箱子只装了6件,其余箱子恰好装满。已知箱子数量为整数,且器材总数不超过200件。求这批实验器材的总件数和使用的箱子数量。","answer":"设箱子数量为x个,器材总件数为y件。\n\n根据题意,第一种装法:每箱装8件,剩余12件,可得方程:\n y = 8x + 12 (1)\n\n第二种装法:前(x - 1)个箱子每箱装10件,最后一个箱子装6件,可得方程:\n y = 10(x - 1) + 6 = 10x - 10 + 6 = 10x - 4 (2)\n\n将(1)和(2)联立:\n 8x + 12 = 10x - 4\n移项得:\n 12 + 4 = 10x - 8x\n 16 = 2x\n x = 8\n\n将x = 8代入(1)式:\n y = 8 × 8 + 12 = 64 + 12 = 76\n\n验证第二种装法:前7个箱子装10×7=70件,第8个箱子装6件,共70+6=76件,符合。\n\n又76 < 200,满足条件。\n\n答:这批实验器材共有76件,使用了8个箱子。","explanation":"本题考查二元一次方程组的实际应用。通过设定箱子数和器材总数为未知数,根据两种不同的装箱方式建立两个等量关系,列出方程组并求解。关键在于理解“最后一个箱子只装6件”意味着前(x−1)个箱子是满装的,从而正确列出第二个方程。解题时需注意题目中的隐含条件(总数不超过200),并在最后进行验证。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 09:40:11","updated_at":"2026-01-07 09:40:11","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2768,"subject":"历史","grade":"七年级","stage":"初中","type":"选择题","content":"考古学家在某遗址中发现了大量炭化稻谷、干栏式建筑遗迹和刻画符号的陶器,这些发现最有可能属于哪个新石器时代文化?","answer":"A","explanation":"题干中提到的‘炭化稻谷’表明该地区以水稻种植为主,而水稻主要种植于长江流域;‘干栏式建筑’是适应潮湿环境的典型建筑形式,常见于南方地区;刻画符号的陶器也见于河姆渡遗址。河姆渡文化位于浙江余姚,属于长江流域的新石器时代文化,距今约7000年,符合上述特征。半坡文化位于黄河流域,以粟作农业和半地穴式房屋为特点;大汶口文化和红山文化也主要分布在北方,且不以水稻为主要作物。因此,正确答案为A。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-12 10:40:42","updated_at":"2026-01-12 10:40:42","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"河姆渡文化","is_correct":1},{"id":"B","content":"半坡文化","is_correct":0},{"id":"C","content":"大汶口文化","is_correct":0},{"id":"D","content":"红山文化","is_correct":0}]},{"id":672,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级大扫除中,某学生负责统计擦窗户和拖地的人数。已知擦窗户的人数比拖地人数的2倍少3人,而两项工作总共有27人参与。设拖地的人数为x,则根据题意可列出一元一次方程:___。","answer":"x + (2x - 3) = 27","explanation":"设拖地的人数为x,则擦窗户的人数为2x - 3(因为比拖地人数的2倍少3人)。两项工作总人数为27人,因此拖地人数加上擦窗户人数等于27,即x + (2x - 3) = 27。该方程正确反映了题目中的数量关系,属于一元一次方程的实际应用,符合七年级数学课程要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:22:30","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":428,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"86.2分","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:34:37","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]