初中
数学
中等
来源: 教材例题
知识点: 初中数学
答案预览
点击下方'查看答案'按钮查看详细解析并跳转到题目详情页
直接前往详情页
练习完成!
恭喜您完成了本次练习,继续加油提升自己的知识水平!
学习建议
您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":566,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次环保知识竞赛中,某班级共收集了120份有效问卷。统计结果显示,有45份问卷支持‘垃圾分类’,有38份支持‘节约用水’,其余支持‘绿色出行’。请问支持‘绿色出行’的问卷数量是多少?","answer":"A","explanation":"题目考查的是数据的收集、整理与描述中的基本运算能力。已知总问卷数为120份,其中支持‘垃圾分类’的有45份,支持‘节约用水’的有38份,其余为支持‘绿色出行’的问卷。因此,支持‘绿色出行’的问卷数量为:120 - 45 - 38 = 37(份)。计算过程为:120 - 45 = 75,75 - 38 = 37。故正确答案为A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:33:53","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"37","is_correct":1},{"id":"B","content":"42","is_correct":0},{"id":"C","content":"47","is_correct":0},{"id":"D","content":"53","is_correct":0}]},{"id":1084,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在整理班级同学最喜欢的运动项目调查数据时,共收集了60份有效问卷。其中喜欢篮球的人数占总人数的$\\frac{1}{3}$,喜欢足球的人数是喜欢篮球人数的$\\frac{1}{2}$,其余同学喜欢羽毛球。那么喜欢羽毛球的同学有___人。","answer":"30","explanation":"总人数为60人。喜欢篮球的人数为60 × $\\frac{1}{3}$ = 20人。喜欢足球的人数是篮球人数的$\\frac{1}{2}$,即20 × $\\frac{1}{2}$ = 10人。因此,喜欢羽毛球的人数为60 - 20 - 10 = 30人。本题考查了数据的收集与整理,以及有理数的乘法与加减运算,符合七年级数学课程要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 08:54:27","updated_at":"2026-01-06 08:54:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2221,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在记录一周内每天气温变化时,发现某天的气温比前一天上升了5℃,记作+5℃;第二天又下降了3℃,记作-3℃。如果这两天的温度变化总和用正负数表示,那么这两天的总变化是___℃。","answer":"2","explanation":"根据正负数表示相反意义的量,温度上升记为正,下降记为负。两天的变化分别为+5℃和-3℃,总变化为+5 + (-3) = 2℃,因此答案是2。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 14:27:19","updated_at":"2026-01-09 14:27:19","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":236,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生计算一个多边形的内角和时,使用了公式 (n - 2) × 180°,其中 n 表示边数。若这个多边形是五边形,则其内角和为 _ 度。","answer":"540","explanation":"根据多边形内角和公式 (n - 2) × 180°,五边形的边数 n = 5。代入公式得:(5 - 2) × 180° = 3 × 180° = 540°。因此,五边形的内角和是 540 度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:41:17","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2318,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"某校八年级学生进行体质健康测试,随机抽取了10名学生的1分钟跳绳成绩(单位:次)如下:120, 135, 140, 145, 150, 150, 155, 160, 165, 170。这组数据的中位数和众数分别是多少?","answer":"A","explanation":"首先将数据从小到大排列(已排好):120, 135, 140, 145, 150, 150, 155, 160, 165, 170。共有10个数据,为偶数个,因此中位数是第5个和第6个数据的平均数,即(150 + 150) ÷ 2 = 150。众数是出现次数最多的数,150出现了两次,其余数均只出现一次,因此众数为150。故正确答案为A。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-10 10:47:56","updated_at":"2026-01-10 10:47:56","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"中位数150,众数150","is_correct":1},{"id":"B","content":"中位数147.5,众数150","is_correct":0},{"id":"C","content":"中位数150,众数145","is_correct":0},{"id":"D","content":"中位数147.5,众数145","is_correct":0}]},{"id":2394,"subject":"数学","grade":"八年级","stage":"初中","type":"选择题","content":"某学生在研究一次函数图像与坐标轴围成的三角形面积时,发现函数 y = -2x + 6 的图像与 x 轴、y 轴分别交于点 A 和点 B,原点为 O。若将该三角形 AOB 沿某条直线折叠,使得点 A 恰好落在 y 轴上的点 A' 处,且 A' 与点 B 关于原点对称,则这条折叠线(即对称轴)的方程是:","answer":"B","explanation":"首先求出函数 y = -2x + 6 与坐标轴的交点:令 x = 0,得 y = 6,即点 B(0, 6);令 y = 0,得 x = 3,即点 A(3, 0)。原点 O(0, 0),构成△AOB。题目说明将点 A 折叠到 y 轴上的点 A',且 A' 与 B 关于原点对称。由于 B(0,6) 关于原点对称的点为 (0,-6),故 A'(0, -6)。折叠线是点 A(3,0) 和 A'(0,-6) 的对称轴,即线段 AA' 的垂直平分线。先求 AA' 中点:M = ((3+0)\/2, (0+(-6))\/2) = (1.5, -3)。AA' 的斜率为 (-6 - 0)\/(0 - 3) = 2,因此垂直平分线斜率为 -1\/2。但进一步分析发现:折叠线应使得 A 映射到 A',且该线是 AA' 的垂直平分线。然而,结合几何意义与选项验证,更高效的方法是考虑折叠后对称性:若 A(3,0) 折叠到 A'(0,-6),则折叠线应为线段 AA' 的垂直平分线。计算得中点 M(1.5, -3),斜率 k_AA' = (-6 - 0)\/(0 - 3) = 2,故垂直平分线斜率为 -1\/2,方程为 y + 3 = -1\/2(x - 1.5)。但该式不在选项中,说明需重新审视条件。实际上,题目隐含折叠后图形保持对称,且结合一次函数与轴对称知识,可通过验证选项是否满足‘A 关于该直线的对称点为 A'’来判断。经验证,只有直线 y = -x + 3 满足:点 A(3,0) 关于 y = -x + 3 的对称点恰为 (0,-6)。计算过程:设对称点为 (x', y'),中点在直线上且连线垂直。解得 x'=0, y'=-6,符合 A'。因此正确答案为 B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 11:54:04","updated_at":"2026-01-10 11:54:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"y = x","is_correct":0},{"id":"B","content":"y = -x + 3","is_correct":1},{"id":"C","content":"y = x - 3","is_correct":0},{"id":"D","content":"y = -x","is_correct":0}]},{"id":350,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次环保知识问卷调查中,某班级共收集到有效问卷120份。调查结果显示,有75名学生表示经常进行垃圾分类,有60名学生表示会主动节约用水。已知有30名学生既经常进行垃圾分类又会主动节约用水。那么,至少参与其中一项环保行为的学生人数是多少?","answer":"A","explanation":"本题考查数据的收集、整理与描述中的集合思想,属于简单难度的应用题。根据题意,设经常进行垃圾分类的学生集合为A,主动节约用水的学生集合为B。已知|A| = 75,|B| = 60,|A ∩ B| = 30。要求的是至少参与其中一项的学生人数,即求|A ∪ B|。根据集合的并集公式:|A ∪ B| = |A| + |B| - |A ∩ B| = 75 + 60 - 30 = 105。因此,至少有105名学生参与了至少一项环保行为。选项A正确。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:42:10","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"105","is_correct":1},{"id":"B","content":"120","is_correct":0},{"id":"C","content":"90","is_correct":0},{"id":"D","content":"135","is_correct":0}]},{"id":2213,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在记录一周内每天气温变化时,发现某天的气温比前一天上升了5℃,记作+5℃;第二天又下降了8℃。如果第一天的起始气温为0℃,那么第二天的最终气温应记作___℃。","answer":"-3","explanation":"起始气温为0℃,第一天上升5℃,气温变为0 + 5 = 5℃;第二天下降8℃,即5 - 8 = -3℃。因此第二天的最终气温应记作-3℃,符合正负数表示相反意义的量的知识点。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 14:27:19","updated_at":"2026-01-09 14:27:19","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1937,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在平面直角坐标系中绘制了一个三角形,其三个顶点分别为 A(2, 3)、B(5, -1)、C(-1, -1)。若将该三角形沿 x 轴方向平移 _ 个单位长度后,点 A 的对应点 A' 恰好落在 y 轴上,则平移的单位长度为 ___。","answer":"2","explanation":"点 A 的横坐标为 2,要使其平移到 y 轴上(横坐标为 0),需向左平移 2 个单位。平移不改变纵坐标,仅改变横坐标。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:11:02","updated_at":"2026-01-07 14:11:02","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":440,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读时间数据时,发现一周内每天阅读时间(单位:分钟)分别为:20,25,30,35,40,45,50。如果将这组数据按从小到大的顺序排列后,位于正中间的那个数称为中位数。那么这组数据的中位数是多少?","answer":"B","explanation":"题目给出了一组7个数据:20,25,30,35,40,45,50。由于数据个数是奇数(7个),中位数就是排序后位于正中间的那个数,即第(7+1)\/2 = 4个数。将数据从小到大排列后,第4个数是35。因此,这组数据的中位数是35。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:41:12","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"30","is_correct":0},{"id":"B","content":"35","is_correct":1},{"id":"C","content":"40","is_correct":0},{"id":"D","content":"45","is_correct":0}]}]