初中
数学
中等
来源: 教材例题
知识点: 初中数学
答案预览
点击下方'查看答案'按钮查看详细解析并跳转到题目详情页
直接前往详情页
练习完成!
恭喜您完成了本次练习,继续加油提升自己的知识水平!
学习建议
您在一元一次方程的应用方面掌握良好,但仍有提升空间。建议重点复习方程求解步骤和实际应用问题。
[{"id":434,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"12人","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:37:48","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2836,"subject":"政治","grade":"高三","stage":"高中","type":"选择题","content":"某市政协创新打造\"百姓提案\"工作机制(见下图)。该做法( )","answer":"A","explanation":"②错误,人民群众没有政协提案权;④错误,\"百姓提案\"不必须转化为政协提案才能解决问题;①③正确。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"中等","points":1,"is_active":1,"created_at":"2026-04-08 20:01:23","updated_at":"2026-04-08 20:01:23","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"①体现了政协扎根于民、问计于民、履职为民的人民底色 ②赋予人民群众政协提案权,丰富了人民群众的民主权利","is_correct":1},{"id":"B","content":"①体现了政协扎根于民、问计于民、履职为民的人民底色 ④表明\"百姓提案\"转化为政协提案才能解决群众关心的问题","is_correct":0},{"id":"C","content":"②赋予人民群众政协提案权,丰富了人民群众的民主权利 ③扩大了人民群众有序政治参与,有利于提升公民的政治素质","is_correct":0},{"id":"D","content":"③扩大了人民群众有序政治参与,有利于提升公民的政治素质 ④表明\"百姓提案\"转化为政协提案才能解决群众关心的问题","is_correct":0}]},{"id":1226,"subject":"数学","grade":"七年级","stage":"初中","type":"解答题","content":"某学生在研究一个由多个正方形拼接而成的图形时,发现该图形的周长与所用正方形的个数之间存在某种规律。已知每个正方形的边长为1个单位长度。当使用n个正方形拼接时(要求拼接时正方形之间至少有一条边完全重合,且整体形成一个连通图形),该学生记录了前几组数据如下:\n\n| 正方形个数 n | 1 | 2 | 3 | 4 | 5 |\n|---------------|---|---|---|---|---|\n| 最小可能周长 P | 4 | 6 | 8 | 10 | 12 |\n\n该学生猜想:当n ≥ 1时,最小可能周长P与n满足关系式 P = 2n + 2。\n\n(1) 验证当n = 6时,该猜想是否成立,并说明理由;\n(2) 若该学生用100个这样的正方形拼接成一个尽可能紧凑的矩形(即长和宽最接近),求此时图形的实际周长,并判断是否满足上述猜想;\n(3) 若要求拼接后的图形必须是一个完整的矩形(不允许有空洞或凸起),试建立周长P与正方形个数n之间的函数关系,并求当n = 2025时,所有可能矩形中周长的最小值。","answer":"(1) 当n = 6时,若要使周长最小,应尽可能让正方形紧密排列,减少外露边数。将6个正方形排成2行3列的矩形,其长为3,宽为2,周长为 2×(3+2) = 10。而根据猜想 P = 2×6 + 2 = 14,显然10 < 14,因此猜想不成立。\n\n(2) 用100个正方形拼成尽可能紧凑的矩形,即找两个最接近的因数a和b,使得a×b = 100。最接近的是10×10,即正方形。此时周长为 2×(10+10) = 40。而根据原猜想 P = 2×100 + 2 = 202,远大于40,因此不满足该猜想。\n\n(3) 若图形必须是完整矩形,设长为a,宽为b,且a、b为正整数,a ≤ b,a×b = n。则周长 P = 2(a + b)。要使P最小,应使a和b尽可能接近,即a取不超过√n的最大因数。\n当n = 2025时,√2025 = 45,且45×45 = 2025,因此可拼成边长为45的正方形,此时周长最小为 2×(45+45) = 180。\n故当n = 2025时,所有可能矩形中周长的最小值为180。","explanation":"本题综合考查了几何图形初步、整式的加减、不等式与不等式组以及数据的收集、整理与描述等知识点。第(1)问通过构造具体图形验证猜想,体现数学建模与反例思想;第(2)问引入最优化思想,结合因数分解求最小周长,考查实际问题转化为数学问题的能力;第(3)问建立函数关系并求极值,涉及因数配对与不等式比较,要求学生理解周长与长宽关系,并能通过分析√n附近的因数确定最优解。题目情境新颖,打破传统计算模式,强调逻辑推理与实际应用,符合困难难度要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 10:25:47","updated_at":"2026-01-06 10:25:47","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2188,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在数轴上标记了两个有理数点A和B,点A表示的数是-3\/4,点B位于点A右侧且与点A的距离为1.25个单位长度。若点B表示的数为x,则下列叙述中正确的是:","answer":"B","explanation":"点A表示-3\/4,即-0.75,点B在其右侧1.25个单位,因此x = -0.75 + 1.25 = 0.5。0.5是0和1这两个连续整数的平均数,因此选项B正确。选项A错误,因为x=0.5虽大于0,但题目问的是'一定',而若点B在左侧则可能为负,但本题中B在右侧已确定x=0.5;选项C错误,因为|x|=0.5<1虽成立,但选项表述为'小于1'看似正确,但结合选项B更准确且具数学意义;选项D错误,因为x + (-3\/4) = 0.5 - 0.75 = -0.25,为负数,但此结论依赖于计算,而B揭示了x的结构特征,更符合'正确叙述'的深层要求。综合分析,B为最佳答案。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-09 14:21:04","updated_at":"2026-01-09 14:21:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"x一定大于0","is_correct":0},{"id":"B","content":"x可以表示为两个连续整数的平均数","is_correct":1},{"id":"C","content":"x的绝对值小于1","is_correct":0},{"id":"D","content":"x与-3\/4的和为负数","is_correct":0}]},{"id":2211,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生记录了一周内每天气温的变化情况,以0℃为标准,高于0℃记为正,低于0℃记为负。已知周一到周五的气温变化分别为:+3℃,-2℃,+1℃,-4℃,+2℃。这五天中,气温最高的一天比最低的一天高___℃。","answer":"7","explanation":"首先找出五天中的最高气温和最低气温。气温变化分别为+3℃,-2℃,+1℃,-4℃,+2℃,其中最高的是+3℃,最低的是-4℃。计算温差:3 - (-4) = 3 + 4 = 7。因此,气温最高的一天比最低的一天高7℃。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-09 14:27:19","updated_at":"2026-01-09 14:27:19","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":210,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生用一根长为20厘米的铁丝围成一个长方形,若长方形的长为6厘米,则宽为_空白处_厘米。","answer":"4","explanation":"长方形的周长公式为:周长 = 2 × (长 + 宽)。已知周长为20厘米,长为6厘米,代入公式得:20 = 2 × (6 + 宽)。两边同时除以2,得10 = 6 + 宽,因此宽 = 10 - 6 = 4厘米。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:39:48","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":586,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"2天","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 20:20:34","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":373,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在平面直角坐标系中描出点A(2, 3)和点B(5, 7),然后连接这两点形成一条线段。若该学生想找出这条线段的中点坐标,他应该计算的结果是:","answer":"A","explanation":"求平面直角坐标系中两点所连线段的中点坐标,应使用中点坐标公式:中点坐标 = ((x₁ + x₂) ÷ 2, (y₁ + y₂) ÷ 2)。已知点A(2, 3)和点B(5, 7),则中点横坐标为 (2 + 5) ÷ 2 = 7 ÷ 2 = 3.5,纵坐标为 (3 + 7) ÷ 2 = 10 ÷ 2 = 5。因此,中点坐标为(3.5, 5)。选项A正确。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:49:46","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"(3.5, 5)","is_correct":1},{"id":"B","content":"(4, 5)","is_correct":0},{"id":"C","content":"(3, 4.5)","is_correct":0},{"id":"D","content":"(3.5, 4.5)","is_correct":0}]},{"id":721,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级图书整理活动中,某学生统计了同学们捐赠的图书数量,发现捐赠数量最多的比最少的多8本,而最多的数量是最少的3倍。如果最少捐赠了___本书,那么最多捐赠了___本书。","answer":"4, 12","explanation":"设最少捐赠了x本书,则最多捐赠了3x本书。根据题意,最多比最少多8本,可列方程:3x - x = 8,解得2x = 8,x = 4。因此最少捐赠了4本,最多捐赠了3 × 4 = 12本。本题考查一元一次方程的实际应用,属于简单难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:56:35","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":364,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"在一次班级数学测验中,老师对全班40名学生的成绩进行了统计,制作了频数分布表。已知成绩在80分到89分之间的学生人数占总人数的25%,那么这个分数段的学生有多少人?","answer":"B","explanation":"题目给出了总人数为40人,80分到89分的学生占总人数的25%。要计算该分数段的人数,只需将总人数乘以百分比:40 × 25% = 40 × 0.25 = 10(人)。因此,成绩在80分到89分之间的学生有10人,正确答案是B。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:46:12","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"8人","is_correct":0},{"id":"B","content":"10人","is_correct":1},{"id":"C","content":"12人","is_correct":0},{"id":"D","content":"15人","is_correct":0}]}]