初中
数学
中等
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知识点: 初中数学
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-6。该题综合考查正负数在数轴上的实际应用与有理数加减运算,需学生理解方向与正负号的对应关系并进行多步计算。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-09 14:39:22","updated_at":"2026-01-09 14:39:22","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":195,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"小明买了3支铅笔和2本笔记本,共花费18元。已知每本笔记本比每支铅笔贵3元,设每支铅笔的价格为x元,则下列方程正确的是( )。","answer":"A","explanation":"设每支铅笔的价格为x元,根据题意,每本笔记本比每支铅笔贵3元,因此每本笔记本的价格为(x + 3)元。小明买了3支铅笔,总价为3x元;买了2本笔记本,总价为2(x + 3)元。两者相加等于总花费18元,因此方程为:3x + 2(x + 3) = 18。选项A正确。其他选项中,B错误地将笔记本价格设为比铅笔便宜,C和D则颠倒了铅笔和笔记本的数量与单价对应关系,均不符合题意。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:04:01","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3x + 2(x + 3) = 18","is_correct":1},{"id":"B","content":"3x + 2(x - 3) = 18","is_correct":0},{"id":"C","content":"3(x + 3) + 2x = 18","is_correct":0},{"id":"D","content":"3(x - 3) + 2x = 18","is_correct":0}]},{"id":643,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生调查了班级同学最喜欢的运动项目,收集到以下数据:篮球 12 人,足球 8 人,跳绳 5 人,乒乓球 10 人。若要将这些数据整理成频数分布表,则跳绳对应的频数是 ___。","answer":"5","explanation":"频数是指某一类别在数据中出现的次数。题目中明确指出喜欢跳绳的有 5 人,因此跳绳对应的频数就是 5。这是数据整理中的基本概念,属于‘数据的收集、整理与描述’知识点,符合七年级数学课程标准要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:09:21","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":291,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"某学生在整理班级同学的课外阅读情况时,收集了10名同学每周课外阅读时间(单位:小时),数据如下:3,5,4,6,5,7,5,4,6,5。这组数据的众数和中位数分别是多少?","answer":"A","explanation":"首先将数据从小到大排序:3,4,4,5,5,5,5,6,6,7。众数是出现次数最多的数,其中5出现了4次,次数最多,因此众数是5。中位数是数据按顺序排列后位于中间位置的数。由于共有10个数据(偶数个),中位数为第5个和第6个数的平均数,即(5 + 5) ÷ 2 = 5。因此,众数是5,中位数是5,正确答案是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:32:36","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"众数是5,中位数是5","is_correct":1},{"id":"B","content":"众数是4,中位数是5","is_correct":0},{"id":"C","content":"众数是5,中位数是4.5","is_correct":0},{"id":"D","content":"众数是6,中位数是5.5","is_correct":0}]},{"id":335,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学最喜欢的运动项目数据时,制作了如下频数分布表。已知喜欢篮球的人数占总人数的30%,总人数为40人,则喜欢篮球的人数是多少?","answer":"B","explanation":"题目要求计算喜欢篮球的人数。已知总人数为40人,喜欢篮球的人数占总人数的30%。计算方法是:40 × 30% = 40 × 0.3 = 12。因此,喜欢篮球的人数是12人。本题考查的是数据的收集、整理与描述中的百分比计算,属于七年级数学中数据处理的基础知识,难度为简单。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 15:39:57","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"10","is_correct":0},{"id":"B","content":"12","is_correct":1},{"id":"C","content":"15","is_correct":0},{"id":"D","content":"18","is_correct":0}]},{"id":547,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"45","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 19:04:55","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":968,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生测量了一个长方形花坛的长和宽,记录数据时不小心把单位弄混了。已知花坛的实际周长是 12 米,长比宽多 2 米。如果设宽为 x 米,则根据题意可列出一元一次方程:______ = 12。","answer":"2(x + x + 2)","explanation":"根据题意,设宽为 x 米,则长为 (x + 2) 米。长方形的周长公式为:周长 = 2 × (长 + 宽)。代入得:2 × (x + x + 2) = 12。因此空白处应填写 2(x + x + 2)。该题考查一元一次方程的实际应用,符合七年级数学课程要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 04:04:02","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":12,"subject":"语文","grade":"初一","stage":"初中","type":"选择题","content":"《朝花夕拾》的作者是?","answer":"A","explanation":"《朝花夕拾》是鲁迅创作的回忆性散文集。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-08-29 16:33:04","updated_at":"2025-08-29 16:33:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"鲁迅","is_correct":1},{"id":"B","content":"郭沫若","is_correct":0},{"id":"C","content":"茅盾","is_correct":0},{"id":"D","content":"老舍","is_correct":0}]},{"id":580,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级进行了一次数学测验,成绩分布如下表所示。老师想计算全班的平均分,但发现表格中缺少一个数据。已知全班共有40名学生,其中90分以上有8人,80~89分有12人,70~79分有10人,60~69分有x人,60分以下有5人。如果全班平均分为75分,那么60~69分的学生人数x是多少?","answer":"C","explanation":"首先根据总人数建立方程:8 + 12 + 10 + x + 5 = 40,解得x = 5。接着验证平均分是否合理:假设各分数段取中间值计算总分,90分以上按95分计,80~89按85分计,70~79按75分计,60~69按65分计,60分以下按55分计。则总分为:8×95 + 12×85 + 10×75 + 5×65 + 5×55 = 760 + 1020 + 750 + 325 + 275 = 3130。平均分为3130 ÷ 40 = 78.25,略高于75,说明估算偏高,但题目仅要求通过人数关系求解x,而人数总和必须为40,因此x = 5是唯一满足条件的整数解。本题考查数据的收集与整理以及一元一次方程的应用,难度为简单。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 20:09:18","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3","is_correct":0},{"id":"B","content":"4","is_correct":0},{"id":"C","content":"5","is_correct":1},{"id":"D","content":"6","is_correct":0}]}]