初中
数学
中等
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知识点: 初中数学
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2) × 180度。根据题意,内角和是外角和的3倍,即(n - 2) × 180 = 3 × 360。计算得(n - 2) × 180 = 1080,两边同时除以180得n - 2 = 6,解得n = 8。因此,这个多边形是八边形。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"中等","points":1,"is_active":1,"created_at":"2025-12-29 14:55:38","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1709,"subject":"数学","grade":"七年级","stage":"初中","type":"解答题","content":"已知关于x的一元一次方程 $ 3(a - 2x) = 5x + 2a $ 的解与方程 $ \\frac{2x - 1}{3} = x - 2 $ 的解互为相反数。求代数式 $ a^2 - 4a + 5 $ 的值。","answer":"**解题步骤:**\n\n**第一步:求第二个方程的解**\n\n解方程:$ \\frac{2x - 1}{3} = x - 2 $\n\n两边同乘以3,去分母:\n$$\n2x - 1 = 3(x - 2)\n$$\n展开右边:\n$$\n2x - 1 = 3x - 6\n$$\n移项:\n$$\n2x - 3x = -6 + 1\n$$\n$$\n-x = -5\n$$\n解得:\n$$\nx = 5\n$$\n\n所以,第二个方程的解是 $ x = 5 $。\n\n根据题意,第一个方程的解与它互为相反数,因此第一个方程的解为 $ x = -5 $。\n\n**第二步:将 $ x = -5 $ 代入第一个方程,求 $ a $ 的值**\n\n第一个方程:$ 3(a - 2x) = 5x + 2a $\n\n代入 $ x = -5 $:\n$$\n3(a - 2 \\times (-5)) = 5 \\times (-5) + 2a\n$$\n$$\n3(a + 10) = -25 + 2a\n$$\n$$\n3a + 30 = -25 + 2a\n$$\n移项:\n$$\n3a - 2a = -25 - 30\n$$\n$$\na = -55\n$$\n\n**第三步:求代数式 $ a^2 - 4a + 5 $ 的值**\n\n将 $ a = -55 $ 代入:\n$$\n(-55)^2 - 4 \\times (-55) + 5 = 3025 + 220 + 5 = 3250\n$$\n\n**最终答案:** $ \\boxed{3250} $","explanation":"本题综合考查了一元一次方程的解法、相反数的概念以及代数式求值。解题关键在于:\n\n1. **先解出已知方程的解**:通过去分母、移项、合并同类项等步骤,准确求出第二个方程的解 $ x = 5 $;\n2. **利用相反数关系转化条件**:由题意,第一个方程的解为 $ -5 $,这是连接两个方程的桥梁;\n3. **代入求解参数 $ a $**:将 $ x = -5 $ 代入含参方程,解出未知参数 $ a $;\n4. **代数式求值**:最后将 $ a $ 的值代入目标代数式,注意运算顺序和符号处理,尤其是负数的平方和乘法。\n\n本题难度较高,体现在需要逆向思维(由解反推参数)和多步逻辑推理,同时涉及分式方程和含参方程,对学生的综合能力要求较高,符合七年级下学期一元一次方程章节的拓展要求。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 14:01:55","updated_at":"2026-01-06 14:01:55","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":238,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"某学生在计算一个数的相反数时,误将该数加上了3,结果得到5。那么这个数的正确相反数应该是____。","answer":"-2","explanation":"设这个数为x。根据题意,某学生误将x加上3得到5,即x + 3 = 5,解得x = 2。这个数的相反数是-2。因此,正确答案是-2。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:41:33","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"若x=3是方程2x + a = 7的解,则a的值为?","answer":"A","explanation":"将x=3代入方程2x + a = 7,得2*3 + a = 7,解得a = 1。","solution_steps":"1. 理解题意;2. 列出已知条件;3. 选择合适的方法;4. 进行计算;5. 验证答案","common_mistakes":"1. 移项时忘记变号;2. 计算错误;3. 未验证答案","learning_suggestions":"1. 多练习一元一次方程;2. 注意符号变化;3. 养成验证习惯","difficulty":"简单","points":1,"is_active":1,"created_at":"2025-08-29 16:33:04","updated_at":"2025-11-17 17:13:31","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"1","is_correct":1},{"id":"B","content":"-1","is_correct":0},{"id":"C","content":"2","is_correct":0},{"id":"D","content":"3","is_correct":0}]},{"id":213,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生计算一个数的相反数时,将原数 5 写成了 -5,那么他得到的结果与原数的正确相反数相比,相差____。","answer":"10","explanation":"原数是 5,它的正确相反数是 -5。某学生误将原数当作 -5,计算其相反数得到 -(-5) = 5。正确结果是 -5,而学生得到的是 5,两者相差 5 - (-5) = 10。因此答案是 10。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 14:40:00","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]