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[{"id":749,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级大扫除中,某学生负责统计清洁工具的分配情况。已知每2名学生共用1把扫帚,每3名学生共用1个拖把,每4名学生共用1个水桶。如果总共使用了26件清洁工具,那么参加大扫除的学生人数是___人。","answer":"24","explanation":"设参加大扫除的学生人数为x。根据题意,扫帚的数量为x\/2,拖把的数量为x\/3,水桶的数量为x\/4。总工具数为26件,因此可列方程:x\/2 + x\/3 + x\/4 = 26。通分后得(6x + 4x + 3x)\/12 = 26,即13x\/12 = 26。两边同乘以12,得13x = 312,解得x = 24。因此,参加大扫除的学生人数是24人。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 23:22:54","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":616,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"(2, 7) 和 (5, 7)","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:41:24","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1490,"subject":"数学","grade":"七年级","stage":"初中","type":"解答题","content":"某学校组织七年级学生开展‘校园绿化角’项目,计划在矩形花坛中种植不同种类的植物。花坛的长比宽多4米,若将长减少2米,宽增加3米,则新花坛的面积比原来增加18平方米。现需在花坛四周铺设宽度相同的步行道,使得整个区域(花坛+步行道)的外轮廓仍为一个矩形,且其周长为60米。已知步行道的铺设成本为每平方米80元,求铺设步行道的总费用。","answer":"设原花坛的宽为x米,则长为(x + 4)米。\n\n根据题意,原面积为:x(x + 4) = x² + 4x(平方米)\n\n长减少2米,变为(x + 4 - 2) = (x + 2)米;\n宽增加3米,变为(x + 3)米;\n新面积为:(x + 2)(x + 3) = x² + 5x + 6(平方米)\n\n由题意得:新面积比原面积多18平方米,列方程:\n(x² + 5x + 6) - (x² + 4x) = 18\n化简得:x + 6 = 18\n解得:x = 12\n\n因此,原花坛宽为12米,长为16米。\n\n设步行道的宽度为y米,则整个区域(含步行道)的长为(16 + 2y)米,宽为(12 + 2y)米。\n\n整个区域的周长为60米,列方程:\n2[(16 + 2y) + (12 + 2y)] = 60\n化简:2(28 + 4y) = 60 → 56 + 8y = 60 → 8y = 4 → y = 0.5\n\n步行道宽度为0.5米。\n\n整个区域面积:(16 + 2×0.5)(12 + 2×0.5) = 17 × 13 = 221(平方米)\n原花坛面积:16 × 12 = 192(平方米)\n步行道面积:221 - 192 = 29(平方米)\n\n铺设费用:29 × 80 = 2320(元)\n\n答:铺设步行道的总费用为2320元。","explanation":"本题综合考查了一元一次方程、整式的加减、几何图形初步及实际问题建模能力。首先通过设未知数表示花坛的长和宽,利用面积变化建立一元一次方程,求出原花坛尺寸。接着引入步行道宽度作为新未知数,结合矩形周长公式建立第二个方程,解出步行道宽度。最后通过面积差计算步行道面积,并结合单价求总费用。题目融合了代数运算与几何图形分析,要求学生具备较强的逻辑推理和综合应用能力,属于困难难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 12:00:17","updated_at":"2026-01-06 12:00:17","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2498,"subject":"数学","grade":"九年级","stage":"初中","type":"选择题","content":"某学生设计了一个圆形花坛,其外围铺设了一条宽度均匀的环形步道。已知花坛的半径为3米,整个花坛与步道合起来的总面积为25π平方米。若设步道宽度为x米,则可列出一元二次方程求解x。根据题意,下列方程正确的是:","answer":"A","explanation":"花坛半径为3米,步道宽度为x米,且步道均匀围绕花坛一周,因此整个结构(花坛+步道)的外圆半径为3 + x米。整个区域的总面积为外圆面积,即π(3 + x)²。题目给出总面积为25π平方米,因此可列出方程:π(3 + x)² = 25π。两边同时除以π,得(3 + x)² = 25,解得x = 2(舍去负值)。选项A正确反映了这一关系。选项B错误地将直径增加当作半径增加;选项C是展开后的形式但未体现几何意义;选项D表示半径减小,与题意不符。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-10 15:19:44","updated_at":"2026-01-10 15:19:44","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"π(3 + x)² = 25π","is_correct":1},{"id":"B","content":"π(3 + 2x)² = 25π","is_correct":0},{"id":"C","content":"πx² + 6πx = 25π","is_correct":0},{"id":"D","content":"π(3 - x)² = 25π","is_correct":0}]},{"id":2241,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在数轴上从原点出发,先向右移动8个单位长度,再向左移动12个单位长度,接着向右移动5个单位长度,最后向左移动3个单位长度。此时该学生所在位置的数是___。","answer":"-2","explanation":"向右移动表示加上正数,向左移动表示加上负数。计算过程为:0 + 8 + (-12) + 5 + (-3) = (8 + 5) + (-12 - 3) = 13 - 15 = -2。因此最终位置对应的数是-2。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-09 14:39:22","updated_at":"2026-01-09 14:39:22","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":528,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级组织了一次环保活动,收集废旧纸张进行回收。第一组收集了15.6千克,第二组收集的比第一组多3.4千克,第三组收集的是第二组的一半。请问第三组收集了多少千克废旧纸张?","answer":"A","explanation":"首先计算第二组收集的纸张重量:15.6 + 3.4 = 19.0(千克)。然后计算第三组的收集量,是第二组的一半:19.0 ÷ 2 = 9.5(千克)。因此,第三组收集了9.5千克,正确答案是A。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:32:55","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"9.5","is_correct":1},{"id":"B","content":"10.2","is_correct":0},{"id":"C","content":"19.0","is_correct":0},{"id":"D","content":"18.5","is_correct":0}]},{"id":445,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"这组数据的众数是85","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:43:57","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":18,"subject":"地理","grade":"初一","stage":"初中","type":"选择题","content":"世界上面积最大的洲是?","answer":"A","explanation":"亚洲是世界上面积最大、人口最多的大洲。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-08-29 16:33:04","updated_at":"2025-08-29 16:33:04","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"亚洲","is_correct":1},{"id":"B","content":"非洲","is_correct":0},{"id":"C","content":"北美洲","is_correct":0},{"id":"D","content":"南美洲","is_correct":0}]},{"id":1774,"subject":"数学","grade":"七年级","stage":"初中","type":"解答题","content":"某学生在平面直角坐标系中绘制了一个由三个顶点组成的三角形,其顶点坐标分别为 A(2, 3)、B(−1, −2) 和 C(4, −1)。该学生先将三角形 ABC 沿 x 轴正方向平移 3 个单位,再沿 y 轴负方向平移 2 个单位,得到新的三角形 A'B'C'。接着,该学生以原点为位似中心,将三角形 A'B'C' 放大为原来的 2 倍,得到三角形 A''B''C''。已知三角形 A''B''C'' 的面积为 S,求 S 的值。","answer":"第一步:平移变换\n原三角形顶点坐标:\nA(2, 3),B(−1, −2),C(4, −1)\n\n沿 x 轴正方向平移 3 个单位,横坐标加 3;\n沿 y 轴负方向平移 2 个单位,纵坐标减 2。\n\n平移后顶点坐标为:\nA'(2+3, 3−2) = (5, 1)\nB'(−1+3, −2−2) = (2, −4)\nC'(4+3, −1−2) = (7, −3)\n\n第二步:位似变换(以原点为中心,放大 2 倍)\n将 A'B'C' 的每个坐标乘以 2:\nA''(5×2, 1×2) = (10, 2)\nB''(2×2, −4×2) = (4, −8)\nC''(7×2, −3×2) = (14, −6)\n\n第三步:计算三角形 A''B''C'' 的面积\n使用坐标法求三角形面积公式:\n面积 = 1\/2 |x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|\n\n代入 A''(10, 2),B''(4, −8),C''(14, −6):\n面积 = 1\/2 |10×(−8 − (−6)) + 4×(−6 − 2) + 14×(2 − (−8))|\n= 1\/2 |10×(−2) + 4×(−8) + 14×(10)|\n= 1\/2 |−20 − 32 + 140|\n= 1\/2 |88|\n= 44\n\n因此,S = 44。","explanation":"本题综合考查平面直角坐标系中的图形变换(平移与位似)以及三角形面积的坐标计算。解题关键在于正确执行两次变换:先平移后位似,注意变换顺序不可颠倒。位似变换以原点为中心,只需将坐标乘以比例因子。面积计算采用坐标公式,代入时注意符号和运算顺序。整个过程体现了图形变换与代数运算的结合,难度较高,适合综合能力考查。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-06 15:13:38","updated_at":"2026-01-06 15:13:38","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":602,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"2小时","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:13:00","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]