1
/ 10
中等
第 1 题
已完成 0 题
练习设置
题目内容
数学
初中
选择题
请选择一道题目开始练习
我的笔记
答案解析
请选择一道题目查看解析
练习完成!
恭喜您完成了本次练习
0
总题数
0
正确
0
错误
答题卡
[{"id":144,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"小明在解一个一元一次方程时,将方程 3x + 5 = 20 的解法写成了以下步骤:第一步,3x = 20 - 5;第二步,3x = 15;第三步,x = 5。小红说小明的解法完全正确,小刚说小明漏掉了检验步骤。根据初一数学的学习要求,以下说法正确的是:","answer":"B","explanation":"根据初一数学课程标准,解一元一次方程的核心是运用等式的基本性质进行变形。小明的解法中,第一步利用等式两边同时减去5,第二步化简,第三步两边同时除以3,每一步都正确。虽然在实际教学中常建议检验,但题目问的是‘解法是否正确’,而非‘是否完整’。只要变形过程正确且结果无误,解法就是正确的。因此选项B正确。选项D强调‘必须检验’,但课程标准并未强制要求每一步解答都必须写出检验,故不选。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-24 11:30:06","updated_at":"2025-12-24 11:30:06","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"小明的解法错误,因为第一步不应该移项","is_correct":0},{"id":"B","content":"小明的解法正确,因为每一步都符合等式性质,且结果正确","is_correct":1},{"id":"C","content":"小明的解法错误,因为第三步应该写成 x = 15 ÷ 3","is_correct":0},{"id":"D","content":"小明的解法不完整,必须写出检验过程才算完整解答","is_correct":0}]},{"id":1013,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次环保活动中,某班级收集了可回收垃圾共120千克,其中纸张占总重量的五分之三,塑料占总重量的四分之一,其余为金属。那么金属的重量是___千克。","answer":"18","explanation":"首先计算纸张的重量:120 × 3\/5 = 72 千克;然后计算塑料的重量:120 × 1\/4 = 30 千克;纸张和塑料共重 72 + 30 = 102 千克;因此金属的重量为 120 - 102 = 18 千克。本题考查有理数中的分数乘法与加减运算在实际问题中的应用。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 05:24:02","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":622,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某班级进行了一次数学测验,老师将全班学生的成绩按分数段整理成如下表格:\n\n| 分数段(分) | 人数(人) |\n|--------------|------------|\n| 60以下 | 3 |\n| 60~69 | 5 |\n| 70~79 | 8 |\n| 80~89 | 10 |\n| 90~100 | 4 |\n\n请问这次测验中,成绩在80分及以上的学生人数占总人数的百分比是多少?","answer":"B","explanation":"首先计算总人数:3 + 5 + 8 + 10 + 4 = 30(人)。\n成绩在80分及以上的学生包括80~89分和90~100分两个分数段,人数为10 + 4 = 14(人)。\n然后计算百分比:14 ÷ 30 × 100% ≈ 46.67%,四舍五入后最接近的选项是45%。\n因此,正确答案是B。\n本题考查的是数据的收集、整理与描述中的频数分布和百分数计算,属于简单难度,符合七年级数学课程内容。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:48:37","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"40%","is_correct":0},{"id":"B","content":"45%","is_correct":1},{"id":"C","content":"50%","is_correct":0},{"id":"D","content":"55%","is_correct":0}]},{"id":1081,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在一次班级环保活动中,某学生收集了废旧纸张和塑料瓶共30件。已知每张废旧纸张可兑换0.2元,每个塑料瓶可兑换0.5元,该学生共获得10.8元。若设废旧纸张有x张,则可列出一元一次方程为:____ + 0.5(30 - x) = 10.8","answer":"0.2x","explanation":"题目中已知废旧纸张和塑料瓶总数为30件,设废旧纸张有x张,则塑料瓶有(30 - x)个。每张废旧纸张兑换0.2元,因此x张可兑换0.2x元;每个塑料瓶兑换0.5元,(30 - x)个可兑换0.5(30 - x)元。总金额为10.8元,所以方程为:0.2x + 0.5(30 - x) = 10.8。空白处应填写的是废旧纸张兑换的金额部分,即0.2x。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 08:54:09","updated_at":"2026-01-06 08:54:09","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1103,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"某学生在整理班级同学的身高数据时,随机抽取了10名学生的身高(单位:厘米)如下:152, 148, 155, 150, 153, 149, 154, 151, 150, 152。这组数据的中位数是______。","answer":"151.5","explanation":"首先将这组数据按从小到大的顺序排列:148, 149, 150, 150, 151, 152, 152, 153, 154, 155。由于数据个数为10(偶数),中位数是中间两个数的平均值,即第5个数151和第6个数152的平均值:(151 + 152) ÷ 2 = 151.5。因此,这组数据的中位数是151.5。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2026-01-06 08:58:02","updated_at":"2026-01-06 08:58:02","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2173,"subject":"数学","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在数轴上标记了三个有理数 a、b、c,已知 a < b < c,且 a 与 c 互为相反数,b 是 a 与 c 的中点。若 |a| = 5,则下列叙述中正确的是:","answer":"B","explanation":"由题意,a 与 c 互为相反数,且 |a| = 5,因此 a = -5 或 a = 5。又因为 a < b < c,若 a = 5,则 c = -5,此时 a > c,与 a < c 矛盾,故 a ≠ 5,只能 a = -5,c = 5。b 是 a 与 c 的中点,即 b = (a + c) \/ 2 = (-5 + 5) \/ 2 = 0。因此 a = -5,c = 5,b = 0,满足 a < b < c。选项 B 正确。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-09 14:12:20","updated_at":"2026-01-09 14:12:20","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"b 的值为 0,c 的值为 -5","is_correct":0},{"id":"B","content":"a 的值为 -5,c 的值为 5,b 的值为 0","is_correct":1},{"id":"C","content":"a 的值为 5,c 的值为 -5,b 的值为 0","is_correct":0},{"id":"D","content":"a 的值为 -5,c 的值为 5,b 的值为 5","is_correct":0}]},{"id":1875,"subject":"语文","grade":"七年级","stage":"初中","type":"选择题","content":"某学生在整理班级同学的课外阅读情况时,收集了以下数据:全班40人,每人每周阅读时间(单位:小时)分布在区间[1, 10]内,且均为整数。他将数据分为5组,每组8人,并计算出每组的平均阅读时间分别为:3.5、4.25、5.0、6.75、8.0。若该学生想用这些数据绘制一个频数分布直方图,并发现其中某一组的实际总阅读时间比按平均数估算的总时间多出2小时,则该组最可能是哪一组?","answer":"C","explanation":"本题考查数据的收集、整理与描述,以及对平均数与总和关系的理解。每组有8人,因此按平均数估算的总阅读时间 = 平均数 × 8。实际总时间比估算多出2小时,说明该组的实际总和 = 平均数 × 8 + 2。由于每人阅读时间为整数,总时间也必为整数。我们逐项分析:A组:3.5 × 8 = 28,+2 = 30(整数,可能);B组:4.25 × 8 = 34,+2 = 36(整数,可能);C组:6.75 × 8 = 54,+2 = 56(整数,可能);D组:8.0 × 8 = 64,+2 = 66(整数,可能)。但关键在于“平均数为6.75”意味着总和为54,而54 ÷ 8 = 6.75,说明原始数据总和为54。若实际多出2小时,则总和为56,平均为7.0。但题目说“按平均数估算”是基于报告的6.75,而实际更高,说明原始分组数据可能被低估。然而,6.75 = 27\/4,说明总和54是3的倍数,而56不是8的倍数导致平均变为7,这在整数数据中是可能的。但更关键的是,6.75是唯一一个非半整数的平均数(3.5、4.25、5.0、8.0均为0.25的倍数,但6.75也符合),但结合“多出2小时”这一异常,最可能出现在中间偏高组,因为极端组(如3.5或8.0)数据分布受限,而6.75组处于中间偏上,数据波动空间大,更容易出现统计偏差。综合分析,C组最可能因数据分布不均导致估算偏差,故选C。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 09:54:14","updated_at":"2026-01-07 09:54:14","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"平均阅读时间为3.5小时的一组","is_correct":0},{"id":"B","content":"平均阅读时间为4.25小时的一组","is_correct":0},{"id":"C","content":"平均阅读时间为6.75小时的一组","is_correct":1},{"id":"D","content":"平均阅读时间为8.0小时的一组","is_correct":0}]},{"id":652,"subject":"数学","grade":"初一","stage":"小学","type":"填空题","content":"在一次班级大扫除中,某学生负责统计各小组清理的垃圾袋数量。已知第一组清理了3袋,第二组清理了5袋,第三组清理了x袋,三组共清理了12袋垃圾。根据题意列出的一元一次方程是:3 + 5 + x = ___","answer":"12","explanation":"题目中明确指出三组共清理了12袋垃圾,而第一组清理3袋,第二组清理5袋,第三组清理x袋,因此总数量为3 + 5 + x。根据总数量等于12,可得方程:3 + 5 + x = 12。空白处应填写总数12,这是建立一元一次方程的关键步骤,考查学生将实际问题转化为数学表达式的能力。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 22:11:40","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":816,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级数学测验成绩整理中,老师将分数分为5个等级:A(90分及以上)、B(80-89分)、C(70-79分)、D(60-69分)、E(60分以下)。某学生统计后发现,获得B等级的人数比C等级多4人,而C等级的人数是D等级的2倍。如果D等级有5人,那么B等级有___人。","answer":"14","explanation":"根据题意,D等级有5人,C等级的人数是D等级的2倍,因此C等级有 5 × 2 = 10 人。又因为B等级比C等级多4人,所以B等级有 10 + 4 = 14 人。本题考查的是数据的整理与描述中对数量关系的理解与简单推理,属于七年级数学中‘数据的收集、整理与描述’知识点,难度为简单。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 00:36:17","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":460,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"144度","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 17:48:43","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]}]