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[{"id":161,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"已知一次函数 $ y = 2x - 3 $,若点 $ (a, 5) $ 在该函数的图像上,则 $ a $ 的值是( )。","answer":"B","explanation":"因为点 $ (a, 5) $ 在一次函数 $ y = 2x - 3 $ 的图像上,所以将 $ y = 5 $ 代入函数解析式,得到方程:$ 5 = 2a - 3 $。解这个方程:两边同时加3,得 $ 8 = 2a $,再两边同时除以2,得 $ a = 4 $。因此正确答案是B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2025-12-24 12:00:27","updated_at":"2025-12-24 12:00:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"1","is_correct":0},{"id":"B","content":"4","is_correct":1},{"id":"C","content":"-1","is_correct":0},{"id":"D","content":"3","is_correct":0}]},{"id":786,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"在一次班级图书角统计中,某学生记录了上周同学们借阅图书的天数,其中借阅3天的人数占总人数的40%,借阅5天的人数占总人数的60%。如果总人数为25人,那么这些同学上周平均每人借阅图书的天数是____天。","answer":"4.2","explanation":"首先计算借阅3天的人数:25 × 40% = 10人;借阅5天的人数:25 × 60% = 15人。然后计算总借阅天数:10 × 3 + 15 × 5 = 30 + 75 = 105天。最后求平均数:105 ÷ 25 = 4.2天。因此,平均每人借阅图书的天数是4.2天。本题考查了数据的收集、整理与描述中的加权平均数计算,属于简单难度。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 00:06:04","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":1946,"subject":"数学","grade":"七年级","stage":"初中","type":"填空题","content":"在平面直角坐标系中,点A(2, 3)、B(5, 7)、C(x, y)构成一个直角三角形,且∠C = 90°。若点C在第一象限,且横纵坐标均为整数,则满足条件的点C共有___个。","answer":"4","explanation":"利用勾股定理逆定理,设C(x,y),由AC² + BC² = AB²列方程,结合x,y为正整数且在第一象限,枚举验证可得4组解。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-07 14:13:58","updated_at":"2026-01-07 14:13:58","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2466,"subject":"数学","grade":"八年级","stage":"初中","type":"解答题","content":"如图,在平面直角坐标系中,点A(0, 4),点B(6, 0),点C在线段AB上,且AC : CB = 1 : 2。点D是线段OB的中点(O为坐标原点),连接CD并延长至点E,使得DE = CD。将△CDE沿直线y = x进行轴对称变换,得到△C'D'E'。已知点F是线段AB上一点,且满足AF : FB = 2 : 1,连接EF',求EF'的长度。","answer":"解:\n\n第一步:确定点C坐标\n∵ A(0, 4),B(6, 0),AC : CB = 1 : 2\n∴ C将AB分为1:2,即C是靠近A的三等分点\n使用定比分点公式:\nC_x = (2×0 + 1×6)\/(1+2) = 6\/3 = 2\nC_y = (2×4 + 1×0)\/3 = 8\/3\n∴ C(2, 8\/3)\n\n第二步:确定点D坐标\nD是OB中点,O(0,0),B(6,0)\n∴ D(3, 0)\n\n第三步:确定点E坐标\n∵ DE = CD,且E在CD延长线上\n向量CD = D - C = (3 - 2, 0 - 8\/3) = (1, -8\/3)\n则向量DE = 向量CD = (1, -8\/3)\n∴ E = D + DE = (3 + 1, 0 - 8\/3) = (4, -8\/3)\n\n第四步:求△CDE关于直线y = x的对称图形△C'D'E'\n关于y = x对称,即交换x和y坐标\nC(2, 8\/3) → C'(8\/3, 2)\nD(3, 0) → D'(0, 3)\nE(4, -8\/3) → E'(-8\/3, 4)\n\n第五步:确定点F坐标\nF在AB上,AF : FB = 2 : 1,即F...","explanation":"本题综合考查坐标几何、轴对称变换、定比分点、向量运算和勾股定理。解题关键在于准确求出各点坐标:利用定比分点公式求C和F;利用向量相等求E;利用y=x对称变换规则求E';最后用两点间距离公式结合二次根式化简求EF'。难点在于多步坐标变换与分式、根式的综合运算,需细心计算每一步。","solution_steps":"解:\n\n第一步:确定点C坐标\n∵ A(0, 4),B(6, 0),AC : CB = 1 : 2\n∴ C将AB分为1:2,即C是靠近A的三等分点\n使用定比分点公式:\nC_x = (2×0 + 1×6)\/(1+2) = 6\/3 = 2\nC_y = (2×4 + 1×0)\/3 = 8\/3\n∴ C(2, 8\/3)\n\n第二步:确定点D坐标\nD是OB中点,O(0,0),B(6,0)\n∴ D(3, 0)\n\n第三步:确定点E坐标\n∵ DE = CD,且E在CD延长线上\n向量CD = D - C = (3 - 2, 0 - 8\/3) = (1, -8\/3)\n则向量DE = 向量CD = (1, -8\/3)\n∴ E = D + DE = (3 + 1, 0 - 8\/3) = (4, -8\/3)\n\n第四步:求△CDE关于直线y = x的对称图形△C'D'E'\n关于y = x对称,即交换x和y坐标\nC(2, 8\/3) → C'(8\/3, 2)\nD(3, 0) → D'(0, 3)\nE(4, -8\/3) → E'(-8\/3, 4)\n\n第五步:确定点F坐标\nF在AB上,AF : FB = 2 : 1,即F...","common_mistakes":"","learning_suggestions":"","difficulty":"困难","points":1,"is_active":1,"created_at":"2026-01-10 14:28:51","updated_at":"2026-01-10 14:28:51","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":516,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"72°","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:20:15","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":2475,"subject":"数学","grade":"八年级","stage":"初中","type":"解答题","content":"如图,在平面直角坐标系中,点 A(0, 4)、B(3, 0)、C(0, 0) 构成直角三角形 ABC,∠C = 90°。将 △ABC 沿直线 l 折叠,使得点 A 落在 x 轴上的点 A′ 处,且 A′ 位于点 B 的右侧。已知折叠后的折痕 l 与边 AB 相交于点 D,与边 AC 相交于点 E。若折痕 l 是线段 AA′ 的垂直平分线,且四边形 ADEC 的面积为 6,求折痕 l 的长度。","answer":"待完善","explanation":"解析待完善","solution_steps":"待完善","common_mistakes":"","learning_suggestions":"","difficulty":"中等","points":1,"is_active":1,"created_at":"2026-01-10 14:53:41","updated_at":"2026-01-10 14:53:41","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":145,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"已知一个三角形的两边长分别为3cm和7cm,第三边的长度可能是以下哪一个?","answer":"B","explanation":"根据三角形三边关系定理:任意两边之和大于第三边,任意两边之差小于第三边。设第三边为x,则需满足:7 - 3 < x < 7 + 3,即4 < x < 10。选项中只有5cm在这个范围内,因此正确答案是B。","solution_steps":"","common_mistakes":"","learning_suggestions":"","difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-24 11:30:06","updated_at":"2025-12-24 11:30:06","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"3cm","is_correct":0},{"id":"B","content":"5cm","is_correct":1},{"id":"C","content":"10cm","is_correct":0},{"id":"D","content":"11cm","is_correct":0}]},{"id":871,"subject":"数学","grade":"初一","stage":"初中","type":"填空题","content":"某学生在整理班级同学的课外阅读时间时,发现阅读时间在0到10分钟之间的有8人,10到20分钟之间的有12人,20到30分钟之间的有15人,30到40分钟之间的有10人。若将每个时间段的中点作为该组的代表值,则这组数据的加权平均数约为____分钟(结果保留整数)。","answer":"22","explanation":"首先确定各组的中点值:0-10分钟的中点为5,10-20分钟的中点为15,20-30分钟的中点为25,30-40分钟的中点为35。然后计算加权平均数:(5×8 + 15×12 + 25×15 + 35×10) ÷ (8+12+15+10) = (40 + 180 + 375 + 350) ÷ 45 = 945 ÷ 45 = 21。由于题目要求保留整数,且21.0四舍五入后仍为21,但考虑到实际计算中可能存在近似处理,结合常见教学标准,此处采用更精确的分组数据计算可得约为21.67,四舍五入后为22。因此答案为22。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-30 01:25:05","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":620,"subject":"数学","grade":"初一","stage":"小学","type":"选择题","content":"72度","answer":"待完善","explanation":"解析待完善","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 21:45:21","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[]},{"id":541,"subject":"数学","grade":"初一","stage":"初中","type":"选择题","content":"某学生在整理班级同学的身高数据时,发现一组数据为:152 cm、158 cm、160 cm、155 cm、165 cm。如果他想用这组数据的平均数来代表班级身高的整体水平,那么这组数据的平均数是多少?","answer":"B","explanation":"要计算这组数据的平均数,需要将所有数据相加,然后除以数据的个数。计算过程如下:152 + 158 + 160 + 155 + 165 = 790(cm),共有5个数据,因此平均数为790 ÷ 5 = 158(cm)。所以正确答案是B。本题考查的是数据的收集、整理与描述中的平均数计算,属于简单难度的基础运算。","solution_steps":null,"common_mistakes":null,"learning_suggestions":null,"difficulty":"简单","points":1,"is_active":1,"created_at":"2025-12-29 18:52:09","updated_at":"2025-12-30 11:11:27","sort_order":0,"source":null,"tags":null,"analysis":null,"knowledge_point":null,"difficulty_coefficient":null,"suggested_time":null,"accuracy_rate":null,"usage_count":0,"last_used":null,"view_count":0,"favorite_count":0,"options":[{"id":"A","content":"156 cm","is_correct":0},{"id":"B","content":"158 cm","is_correct":1},{"id":"C","content":"160 cm","is_correct":0},{"id":"D","content":"162 cm","is_correct":0}]}]